in reply to Getting an Array Reference Into an Array

Why don't you do this: 

my @myArray = qw/three-point-oh three-point-one three-point-two/;
$myHash{"tres"} = \@myArray;


# then do everything onto @myArray;

push @myArray, "three-point-three", "three-point-four";

# And $myHash is automatically updated

print join(' ', @{$myHash{"tres"}}), "\n";

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Re^2: Getting an Array Reference Into an Array
by qazwart (Scribe) on Jun 07, 2006 at 20:34 UTC
    Why don't you do this: 
    my @myArray = qw/three-point-oh three-point-one three-point-two/;
$myHash{"tres"} = \@myArray;

# then do everything onto @myArray;

    [download]
    Because in my actual program, I'm not creating the array from scratch. The whole datastructure is given to me, and I have to manipulate it and return it back to the calling program.

    In the actual program, it is an array of a hash of a hash, and the array itself could contain thousands of members. That's why I don't want to use dereferencing and that's why I didn't want to copy it.

    I posted a simple program to demonstrate that concept.

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