in reply to Help with scalar values and array as arguments to function
Thanks again, Ronald Vazquezsub format_output { my $var1 = shift; my $var2 = shift; my @array = @_; my $tmp = 0; for ($tmp = 0 ; $tmp <= $#array ; $tmp++) { do_good_stuff_to_array_elements; } } my @array = (); # $scalar carries the binary data @array = split('', $scalar); &format_output(":", 0, @array[8 .. 13]);
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