in reply to how to exec a CGI file with params?

I think you can (should) use include virtual instead of exec cgi...

From the apache mod_include docs: 
If the specified URL is a CGI program, the program will be executed an
+d its output inserted in place of the directive in the parsed file. Y
+ou may include a query string in a CGI url:

<!--#include virtual="/cgi-bin/example.cgi?argument=value" -->

include virtual should be used in preference to exec cgi to include th
+e output of CGI programs into an HTML document.

[download]

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Re^2: how to exec a CGI file with params?
by Anonymous Monk on Jun 17, 2006 at 20:35 UTC
    Hi.

    I can't get it to work yet. For the SSI I am using   <!--#include virtual="day.pl?show=all" --> Inside my day.pl script (it's loading without error now, but it's loading the main script, it's not catching on the param "show".

    my $show  = url_param("show");
my $show1 = param("show");
.
.

if ($show ne "all" || $show1 ne "all")
{

    [download]
    I did show and show1, incase it wasn't passing as a URL param. Neither of them catch. Any idea why?
[reply]
[d/l]
[select]
      To be able to answer your question, we need to see more of your CGI-program.

      CountZero

      "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law

[reply]
        use warnings;
use strict;
use CGI::Carp qw(fatalsToBrowser);
use CGI qw/:standard/;

my $teaser_show = 3;   # number of headlines to show in TEASER mode
my $page_show   = 50;  # number of headlines to show on page
my $intro       = "Hi;  # top message on screen when it's showing all 
+results

print header, start_html();

my $show  = url_param("show");
my $show1 = param("show");


if ($show ne "all" || $show1 ne "all")
{
   print "no SHOW param was found";
}
else
{
   print "this prints if the param is found";
}

        [download]
        Is what I am using right now
[reply]
[d/l]

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