slicing a hash ref

rvosa has asked for the wisdom of the Perl Monks concerning the following question:

Dear monks,

I'm trying to apply slicing semantics to a hash reference, analogous to the following:

%hash = ( 'a' => 1, 'b' => 2 );
print @hash{'a','b'}; # prints '12'
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Now I want to do the same with a hash reference:

$hasref = { 'a' => 1, 'b' => 2 };
# not sure... is it $hashref->{'a','b'}? That just yields 'uninitializ
+ed'.
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Thanks!

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Re: slicing a hash ref by Sidhekin (Priest) on Jul 01, 2006 at 02:59 UTC
There is no arrow syntax, I'm afraid -- you'll have to deref with the sigil: `print @$hashref{'a','a','b'};` If your hashref is the least bit complicated, you'll want to use a block. In fact, you might want to use a block in any case, rather than worry about precedence ... `print @{$hashref}{'a','a','b'}; # @{$hashref{'a','a','b'}} would be dereferencing (as an array) # an element of that arcane structure, a multi-dimensional hash.` [download] `print "Just another Perl ${\(trickster and hacker)},"` The Sidhekin proves Sidhe did it!	[reply] [d/l] [select]
Re: slicing a hash ref (quick) by tye (Sage) on Jul 01, 2006 at 04:10 UTC
references quick reference is how I figured out to make this stuff easy for me to remember. You might find it helpful too. - tye	[reply]