Re^6: Why is the execution order of subexpressions undefined? (why not?)

Be careful what you wish for. Haskell has lazy evaluation, but it is extremely easy to create a program plagued with space leaks. And if you eliminate the automatic memoization, you'll end up turning your space leaks into time leaks.

Comment on Re^6: Why is the execution order of subexpressions undefined? (why not?)

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Re^7: Why is the execution order of subexpressions undefined? (why not?) by diotalevi (Canon) on Jul 15, 2006 at 00:10 UTC
Oh genie? I wish for sanity too. There are places in real code that I want this to happen. ⠤⠤ ⠙⠊⠕⠞⠁⠇⠑⠧⠊	[reply]
Re^8: Why is the execution order of subexpressions undefined? (why not?) by Anonymous Monk on Jul 15, 2006 at 01:54 UTC
I wish for sanity too. There are places in real code that I want this to happen. Delayed evaluation in Perl is spelled `sub`.	[reply] [d/l]