sulfericacid has asked for the wisdom of the Perl Monks concerning the following question:

This was partially discussed in the CB earlier this morning but thought the idea would be easier if there were some examples.

I have a column "time" with timestamps that look like 2006-08-10 10:48:21. I need to select them based on TODAY, THIS WEEK, THIS MONTH, etc.

I am currently using CURDATE(),INTERVAL $by ($by: 1 day, 7 day, etc) which I could probably get by with but it's not quite right. I don't want a "past 24 hours" select, I want a select from today since midnight. On the same token, I don't want the past 7 days, I want this week from Sunday. Same goes for the current month and year.

Selecting an interval on 1 year or even 365 days brings back a year from the current date, not the year of 2006.

I'm looking for non-modular solutions on how this could be pieced together.



"Age is nothing more than an inaccurate number bestowed upon us at birth as just another means for others to judge and classify us"

sulfericacid

2006-08-11 Retitled by planetscape, as per Monastery guidelines

( keep:0 edit:7 reap:2 )

Original title: 'parsing time in mysql'

Replies are listed 'Best First'.
Re: (OT) parsing time in mysql
by Ieronim (Friar) on Aug 11, 2006 at 21:18 UTC
    I think, 
    SELECT * from `your_table_name` WHERE DAY(time) = DAY(NOW())

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    SELECT * from `your_table_name` WHERE 
  YEAR(time) = YEAR(NOW()),
  DAYOFYEAR(time) = DAYOFYEAR(NOW())

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    etc. will work.

    MySQL has corresponding WEEK, YEAR and MONTH functions, too.

    I assumed that you are using MySQL 4.1.1 or above. It not, use DATE_FORMAT with corresponding formatstring instead.

    UPD:I wanted to give a quick and dirty answer, but this answer was TOO dirty :) Bug is now corrected.

         s;;Just-me-not-h-Ni-m-P-Ni-lm-I-ar-O-Ni;;tr?IerONim-?HAcker ?d;print
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      I was really looking for a more PERLish way to do this. I tried this solution and I had odd results. It brought back results from other months that occured on the same day. Today was the 11th, it showed data on the 11th over the past few months.

      Anyway around this?



      "Age is nothing more than an inaccurate number bestowed upon us at birth as just another means for others to judge and classify us"

      sulfericacid
[reply]
        It brought back results from other months that occured on the same day.
        I posted wrong request :( But it can be easily extended to become right: 
        -- today
SELECT * from `your_table_name` WHERE 
  YEAR(time) = YEAR(NOW()),
  DAYOFYEAR(time) = DAYOFYEAR(NOW())

--this month
SELECT * from `your_table_name` WHERE 
  YEAR(time) = YEAR(NOW()),
  MONTH(time) = MONTH(NOW())

--this week (USA) (simple solution with WEEK() 
--won't work at the beginning of the year
SELECT * from `your_table_name` WHERE 
  YEARWEEK(time, 0) = YEARWEEK(NOW(), 0)

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        Rewriting of the request to use DATE_FORMAT can be performed according to the docs.

        I don't know if it's a Perlish way, but it's a RIGHT way. SELECT must select only the data you want, and it's faster and cleaner to perform all heavy-weight data filtering on the database side.

             s;;Just-me-not-h-Ni-m-P-Ni-lm-I-ar-O-Ni;;tr?IerONim-?HAcker ?d;print
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