Re^2: I'm splitting a scalar and putting the results in an array. Why is the first element empty?

I think they apply, unless I am mistaken. Granted, english is not my first language, so I may have misunderstood your post, but it is a normal behaviour for split not to enter the separator in the returned array.
For example, this bit of code :

my $string = "aa:bb:cc:dd:ee:ff:gg:hh";

my @table = split /:/ , $string;

print "@table\n";
[download]

would print

aa
bb
cc
dd
ee
ff
gg
hh
[download]

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Re^3: I'm splitting a scalar and putting the results in an array. Why is the first element empty? by artist (Parson) on Aug 14, 2006 at 14:17 UTC
It does if you have parans in the regex. `my @table = split /(:)/, $string` [download] --Artist	[reply] [d/l]