list comprehension

nmerriweather has asked for the wisdom of the Perl Monks concerning the following question:

Python has something called list comprehension

myInts= [ int(i) for i in getItems() ]
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i know there's some way to do this in perl using map, i just can't figure it out.
i'm specifically trying to int the y/m/d in a date

( y , m , d )= [ int(i) for i in date.split('-') ]
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Re: list comprehension by duckyd (Hermit) on Aug 25, 2006 at 19:01 UTC
I suspect you want something like: `my ( $y, $m, $d ) = map { int } split /-/, '2006-04-03.14159';` [download] Note that int operates on $_ by default, the above is equivalent to map { int($_) }	[reply] [d/l]
Re^2: list comprehension by jwkrahn (Abbot) on Aug 25, 2006 at 19:38 UTC
Or: `my ( $y, $m, $d ) = '2006-04-03.14159' =~ /\d+/g;` [download]	[reply] [d/l]
Re^2: list comprehension by nmerriweather (Friar) on Aug 25, 2006 at 19:26 UTC
thats it. thanks!	[reply]
Re^3: list comprehension by Not_a_Number (Prior) on Aug 25, 2006 at 20:28 UTC
Or even (TMTOWTDI): `my ( $y, $m, $d ) = unpack 'A4xA2xA2', $str;`	[reply] [d/l]