in reply to sub ($self,$var,@arr) {}

And why are you passing @arr around like that. 
my $foo = new Foo;
$foo->Bar($var, \@array);

sub Bar {
    my $self = shift;
    my ($var, $array_ref) = @_;
}

[download]
Get in the habit of passing references around, much nicer to your RAM.

Jeff 

R-R-R--R-R-R--R-R-R--R-R-R--R-R-R--
L-L--L-L--L-L--L-L--L-L--L-L--L-L--

Replies are listed 'Best First'.
Re: (jeffa) Re: sub ($self,$var,@arr) {}
by raptor (Sexton) on Feb 13, 2001 at 15:57 UTC
    sorry long way I wasn't here here is my answer.
    just exapmle I'm not passing in this way..
    And the people can use both ways, why not ..i.e.
    sub mysub ($self)
{
 my @rest = @_;
}

sub mysub ($self,$nextvar1,$nextvar2)
{
...
}

    [download]
    instead of : 
    sub mysub
{
 my ($self,@rest) = @_;
}

OR
sub mysub
{
 my $self = shift;
 ...some code .. $nextvar1 = shift;
 ...code ... 
 $nextvar2 = shift;
}

    [download]
    for me the first is much more clear... and can be used to document what the creator of this sub mostly expected like parameters.. with one RegEx U can extract a desc of methods and so on... this is JMO
[reply]
[d/l]
[select]

In Section Seekers of Perl Wisdom