in reply to How to pass two arrays to a sub?

use strict; use warnings; use Data::Dumper; my @list1 = qw(a b c); my @list2 = qw(d e f); printem([@list1], [@list2]); sub printem { my $list1 = shift or die "no list1"; my $list2 = shift or die "no list2"; print "list1: " . Dumper($list1); print "list2: " . Dumper($list2); }

Replies are listed 'Best First'.
Re^2: How to pass two lists to a sub?
by wazoox (Prior) on Oct 18, 2006 at 11:26 UTC
    Please notice that
    printem([@list1], [@list2]);
    actually creates two anonymous arrays and copy data in memory, while
    printem(\@list1, \@list2)
    will pass references to the original arrays.
    Copying data will prevent accidental changes of the original arrays but may be quite long and memory-hungry if the copied data is big...
    Here's a small sample to picture the difference :
    #!/usr/bin/perl use strict; use warnings; use Data::Dumper; my @list1 = qw(a b c); my @list2 = qw(d e f); sub sem { my $list1 = shift or die "no list1"; my $list2 = shift or die "no list2"; $list1->[0]='x'; @{$list2}=qw(D E F); } # print original data print "list1: " . Dumper(@list1); print "list2: " . Dumper(@list2); # call with copy sem([@list1], [@list2]); print "list1: " . Dumper(@list1); print "list2: " . Dumper(@list2); # call by reference sem(\@list1, \@list2); print "list1: " . Dumper(@list1); print "list2: " . Dumper(@list2);
      Hi
      Thanks a lot for your suggestion.
      Regd's
      Sanjay