in reply to Incorrect pattern recognition problem.

This appears to be a situation when the pattern matches a zero-length substring (see perlre, "Repeated patterns matching zero-length substring"). Using s/.+/t/g gives the expected result.

Update: Adding use re 'debug'; to the code produces some interesting output that illustrates the documented behavior. Note how it says Matching REx ".*" against "" <stuff deleted> Match successful! midway through. If I understand this correctly, that is where it matches the empty string and produces the extra 't' in the output.

Compiling REx `.*' size 3 Got 28 bytes for offset annotations. first at 2 1: STAR(3) 2: REG_ANY(0) 3: END(0) anchored(MBOL) implicit minlen 0 Offsets: [3] 2[1] 1[1] 3[0] Matching REx ".*" against "abc" Setting an EVAL scope, savestack=5 0 <> <abc> | 1: STAR REG_ANY can match 3 times out of 2147483647 +... Setting an EVAL scope, savestack=5 3 <abc> <> | 3: END Match successful! Matching REx ".*" against "" Setting an EVAL scope, savestack=5 3 <abc> <> | 1: STAR REG_ANY can match 0 times out of 2147483647 +... Setting an EVAL scope, savestack=5 3 <abc> <> | 3: END Match successful! Matching REx ".*" against "" Setting an EVAL scope, savestack=5 3 <abc> <> | 1: STAR REG_ANY can match 0 times out of 2147483647 +... Setting an EVAL scope, savestack=5 3 <abc> <> | 3: END Match possible, but length=0 is smaller than requested=1, failing! failed... Match failed ttFreeing REx: `".*"'
See perldebguts for more information on interpreting this output.