in reply to Re^2: process array with while loop
in thread process array with while loop

Except that print is not a void context. Therefore the map will create a list. 
#!/usr/bin/perl

use strict;
use warnings;

my $a = ( print "Hello world\n" );
print "The answer is $a\n";

__END__

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See `perldoc -f print` for details.

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Re^4: process array with while loop
by davorg (Chancellor) on Nov 14, 2006 at 14:04 UTC
    Except that print is not a void context.

    I think you might be misunderstanding. blahblah wasn't talking about the call to print. He was talking about the call to map ("map in a void context"). And the call to map is in a void context - its return value doesn't go anywhere. But as he also pointed out, that's no longer a problem. Or, at least, it's not a problem from a technical point of view. I'd still argue that it's not the clearest way to write the code.

    --
    <http://dave.org.uk>

    "The first rule of Perl club is you do not talk about Perl club."
    -- Chip Salzenberg

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