in reply to Re^2: splitting directly to hash
in thread splitting directly to hash
Try to visualise map as an assembly line. The right conveyor belt bring list values one by one and feeds them to the block. The block executes for each of these values and in turn produces zero, one or multiple values which are put on the left conveyor belt.
step 0: () {map} (1 2 3) step 1: (1 undef) {map} (2 3) step 2: (1 undef 2 undef) {map} (3) step 3: (1 undef 2 undef 3 undef) {map} ()
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Re^4: splitting directly to hash
by texasperl (Sexton) on Nov 21, 2006 at 19:36 UTC | |
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Re^4: splitting directly to hash
by OfficeLinebacker (Chaplain) on Nov 22, 2006 at 15:03 UTC |