Re^4: Conditional Operator Confusion

Not really... I'm sure I'm being really dumb here, but I still don't understand, in the following example, why $x gets set to "FALSE"... just very, very confused...

1==1?$x='TRUE':$y='FALSE';
print "x=$x\n";
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Tom Melly, pm@tomandlu.co.uk

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Re^5: Conditional Operator Confusion by ikegami (Patriarch) on Nov 30, 2006 at 17:12 UTC
The conditional operator has higher precedence than the assignment operator, so `$c?$x='TRUE':$y='FALSE'` is the same as `($c?$x='TRUE':$y)='FALSE'` The addition operator has higher precedence than the conditional operator, so `$c?$x+2:$y+3` is the same as `$c?$x+2:($y+3)` If you want to do assignments, use `if` or add parens. Think of as the conditional operator as an operator that returns something.	[reply] [d/l] [select]
Re^6: Conditional Operator Confusion by Melly (Chaplain) on Nov 30, 2006 at 17:25 UTC
Thanks - I think I've finally got it (with some help from the chatterbox as well). All of which goes to confirm something a coworker once told me.. Me: What's the precedence in <lang> for these operators? CW: Who cares? Use brackets - it's easier to read and you won't get screwed... Tom Melly, pm@tomandlu.co.uk	[reply]