in reply to ?: = Obfuscation?

Like most things in perl the ternary operator can both help and hinder readability.

I prefer ternary for this:

# With ternary my $x = exists $hash{key} ? $hash{key} : 'default' # Without my $x; if (exists $hash{key}) { $x = $hash{key}; } else { $x = 'default'; }
I'm on the fence for this:
# With ternary my $x = $x > 5 ? 5 : $x + 1; # With if if ($x > 5) { $x = 5; } else { $x++; }
And dead set against this:
my $x = $y > 5 ? ($y = 0) : ($y = 1);

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Re^2: ?: = Obfuscation?
by ikegami (Patriarch) on Dec 01, 2006 at 20:31 UTC

    And dead set against this:

    my $x = $y > 5 ? ($y = 0) : ($y = 1);

    As you should be.

    my $x = ($y = $y > 5 ? 0 : 1);

    and

    $y = $y > 5 ? 0 : 1; my $x = $y;

    are much more readable.