Re: Tutorial on arguments for the new

sorry, couldn't resist ;-)

update:

foo($bar, $baz); 
# ...
sub foo{        
     print "$_";   
#will first print out the contents of $bar, then $baz 
...
[download]

No it won't.

you mean

sub foo {
  print for @_;
}
# or
sub foo {
  print @_;
}
[download]

"What should it profit a man, if he should win a flame war, yet lose his cool?"

Comment on Re: Tutorial on arguments for the new Select or Download Code

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Re^2: Tutorial on arguments for the new by Andrew_Levenson (Hermit) on Dec 11, 2006 at 21:17 UTC
I was going to start with "I'd like to register a complaint!" but I realized it was the wrong sketch. We'll save that one for the tutorial on getting started with... that other language. And, thanks for pointing that out to me. `C(qw/74 97 104 112/);sub C{while(@_){$c**=$C;print (map{chr($C!=$c?shift:pop)}$_),$C+=@_%2!=1?1:0}}` [download]	[reply] [d/l]
Re^2: Tutorial on arguments for the new by PockMonk (Beadle) on Dec 11, 2006 at 21:21 UTC
I think he was just trying to explain for others starting out what arguments were and how they were passed to subroutines, I don't think the exact code matters all that much. Even clearer might be: `my ($bar, $baz) = ("Hello ", "World"); foo($bar, $baz); # ... sub foo{ print "$_[0]"; #prints "Hello " print "$_[1]"; #prints "World"` [download]	[reply] [d/l]