Illegal hex digit '

thevoid has asked for the wisdom of the Perl Monks concerning the following question:

Another one I'm struggling with - Have been asked to write a program which asks for a hex number to be input and convert it to decimal. I did this -

#!/usr/bin/perl
#converter.plx
use warnings;
use strict;
print "Please input a hex no. to convert to dec. :";
my $value = <STDIN>;
print hex("$value"), "\n";
[download]

It will do the conversion, but I get the error -

Illegal hexadecimal digit '
' ignored at -path- line 7, <STDIN> line 1.
[download]

I don't understand where perl is getting the ' from... cheers

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Re: Illegal hex digit ' by ikegami (Patriarch) on Dec 23, 2006 at 18:58 UTC
We just answered this for you. `$value` contain the newline from pressing Enter. Use `chomp( my $value = <STDIN> );` [download] to remove any trailing newline. Ref: `chomp` By the way, you'll probably never want to do `func("$var")`. Just use `func($var)`.	[reply] [d/l] [select]
Re: Illegal hex digit ' by rhesa (Vicar) on Dec 23, 2006 at 18:34 UTC
It's displaying the newline at the end of the user input (you hit enter, right?). Use chomp to get rid of it: `chomp( my $value = <STDIN> );` [download]	[reply] [d/l]
Re: Illegal hex digit ' by thevoid (Scribe) on Dec 23, 2006 at 19:23 UTC
ooops, chomp again... thanks both	[reply]