in reply to regexp question

Alternatively, you could use the word boundary marker 

  /(.{1,20})\b/g

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In contrast to using \s*, this would prevent individual words from being split across lines, which I guess was the idea behind the space you used...

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Re^2: regexp question
by tfoertsch (Beadle) on Dec 29, 2006 at 11:55 UTC
    This does what I wanted: 
      my @x=/(\S.{0,19})(?=\s|$)/g;

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    Thanks to all
[reply]
[d/l]

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