Re^2: returning tied array

Hi all, (please ignore the "intermidate" thing) as far as i know, returning anything from a sub, object etc, usualy returns an array, sorry dont have time to check the script, but try,

@MyArray = &YourFunction(pass variables here); ## or
$MyString = &YourFunction(pass variables here); ##might work!

--------------
sub YourFunction{
    @array =@_;
    (do something)
    return $YourString;  ##wich ya get a string
    return @YourArray;  ##wich ya get an array, i think the 
                        array objects seperated by spaces!
                       (and furthermore you can change the 
                        space to something else through a 
                        special command to the perl
                        interperter! :P )
    }
---------------
[download]

calling objects is done a different way! :P if your going to pass hashes there is another way to do it, but ya gonna have to ask! :P

c ya, have fun! www.arobcorp.com

Comment on Re^2: returning tied array Download Code

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Re^3: returning tied array by AK108 (Friar) on Jan 08, 2007 at 02:36 UTC
If you return a list from a subroutine, then you get that list back. If it was in scalar context, then you only get the first item of the list. You can use wantarray to see what context you were called in. Update: s/\barray\b/list/g per chromatic's comment.	[reply]
Re^4: returning tied array by chromatic (Archbishop) on Jan 08, 2007 at 04:52 UTC
You can only return scalars and lists and (nothing) from subroutines. You can't return arrays or hashes directly, only as lists or references.	[reply]
Re^5: returning tied array by AK108 (Friar) on Jan 08, 2007 at 13:57 UTC
Good point. I updated my above post to correct that.	[reply]