Re^2: Count of HoA elements

This is wrong. There is absolutely no reason to iterate the hash to count the elements!

c:\test>p1
Perl> %a = 'a' ..'z';;
Perl> print scalar values %a;;
13
[0] Perl> print scalar keys %a;;
13
[download]

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

"Science is about questioning the status quo. Questioning authority".

In the absence of evidence, opinion is indistinguishable from prejudice.

Comment on Re^2: Count of HoA elements Download Code

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Re^3: Count of HoA elements by ikegami (Patriarch) on Jan 19, 2007 at 20:31 UTC
He asked for the number of elements in the HoA. I took that to mean 5 for the following structure: `my %h = ( k1 => [ qw( a b c ) ], k2 => [ qw( d e ) ], );` [download] Your solution simply returns the number of elements in a hash. It could be that's what he meant, but that's now how I interpreted his question. This is wrong. Not so hasty on the wrong. Fletch and Jenda also interpreted the question like I did.	[reply] [d/l]

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Re^3: Count of HoA elements
by ikegami (Patriarch) on Jan 19, 2007 at 20:31 UTC

He asked for the number of elements in the HoA. I took that to mean 5 for the following structure:

my %h = (
   k1 => [ qw( a b c ) ],
   k2 => [ qw( d e ) ],
);
[download]

Your solution simply returns the number of elements in a hash. It could be that's what he meant, but that's now how I interpreted his question.

This is wrong.

Not so hasty on the wrong. Fletch and Jenda also interpreted the question like I did.