variable interpolation

underwarez has asked for the wisdom of the Perl Monks concerning the following question:

I have a function that has several variables called $val1, $val2, ... , $val10. In the function, I call another function that does work on each of the variables i.e. printOp ($val1) printOp ($val2) ... printOp ($val10) ------------------------------------- Is there any way to do this using a loop? i.e. for ( $i = 0 to 10 ) printOp ( $val$i ) }

Comment on variable interpolation

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Re: variable interpolation by merlyn (Sage) on Feb 21, 2001 at 23:58 UTC
I have a function that has several variables called $val1, $val2, ... , $val10. There's your problem. You want `$val[1]` through `$val[10]` instead. And maybe even `$val[0]`. -- Randal L. Schwartz, Perl hacker	[reply] [d/l] [select]
(ichimunki) re: variable interpolation by ichimunki (Priest) on Feb 21, 2001 at 23:59 UTC
read perldata. you want to use a "list" (aka "array") instead of enumerated scalar names.	[reply]
Re: variable interpolation by yakko (Friar) on Feb 22, 2001 at 00:35 UTC
As has been said above, you most likely want a list (bka: array). Let's say you choose `@val`... Here's an example of what you can then do: `foreach my $value (@val) { printOp($value); }` [download] -- Me spell chucker work grate. Need grandma chicken.	[reply] [d/l] [select]