Algorithmic hash bug.

thenetfreaker has asked for the wisdom of the Perl Monks concerning the following question:

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Re: Algorithmic hash bug. by shmem (Chancellor) on Feb 19, 2007 at 08:24 UTC
"without a singl loop" Direct hash lookups indeed work without loops. So how can i correct my mistake ? which mistake? Got some error? Some code, apart from that multilevel hash lookup? From what you say I figure you mean `my $x = $hash{$valueM}{$key};` [download] because you say "where the mainKey equals $valueM". As you have written that multilevel hash lookup, the string contained in $valueM would be one key in an anonymous hash stored as the value for the key 'mainKey' in the hash %hash. I guess that's different to what you wrote. But how can I know? I know what I mean. Why don't you? --shmem _($_=" "x(1<<5)."?\n".q·/)Oo. G°\ / /\_¯/(q / ---------------------------- \__(m.====·.(_("always off the crowd"))."· ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}	[reply] [d/l]
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Re: Algorithmic hash bug. by cdarke (Prior) on Feb 19, 2007 at 13:19 UTC
If I read your question correctly, it is very simple: `$x = $hash{$valuem};` [download] The solution you provided implies: a hash with the key 'mainKey', whose value is a reference to a hash with the key in $valueM, whose value is a reference to a hash with the key 'key'.	[reply] [d/l]
Re: Algorithmic hash bug. by ysth (Canon) on Feb 19, 2007 at 10:20 UTC
"without a singl loop" What are you quoting? A homework assignment? I'm looking for a job.	[reply]
Re: Algorithmic hash bug. by pajout (Curate) on Feb 19, 2007 at 15:24 UTC
I guess that you want something like this: `use strict; use warnings; my $valueM = 'myvalue'; my $hashref; $$hashref{mainKey}{$valueM}{key} = 'value';` [download] or `my %hash; $hash{key} = 'value'; ...` [download]	[reply] [d/l] [select]