in reply to Why are "a ||= b" and "a = a || b" different?
You could just say $ret ||= (foo())[0]; instead.
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Re^2: Why are "a ||= b" and "a = a || b" different?
by ikegami (Patriarch) on Mar 05, 2007 at 07:04 UTC | |
by ambrus (Abbot) on Mar 05, 2007 at 10:15 UTC | |
by ikegami (Patriarch) on Mar 05, 2007 at 14:10 UTC |