Re^3: Reference on List & Arrays Difference

Oh..! Thanks for correcting that. So the (1,2,3,4) is not even interpreted as a list, but as a grouping of operands and operators which evaluation results in the last (rightmost) operand.

You never stop to learn...

--shmem

_($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                              /\_¯/(q    /
----------------------------  \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

Comment on Re^3: Reference on List & Arrays Difference

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Re^4: Reference on List & Arrays Difference by Anno (Deacon) on Mar 11, 2007 at 15:22 UTC
Exactly! As the saying goes: There is no list in scalar context. Anno	[reply]