Re^2: RegEx: How to negate more than one character?

thanks... but I am looking for the particular negation to be part of a much more complex overall regular expression... i.e., how can i do the negation within the expression itself, rather than relying on !~?

What I am trying to do is match outermost <% ... %> "brackets" while also handling possible internal pairs of my own unique bracketing system:

$re = qr{\<\%(?:(?>[^(\<\%|\%\>)]+)|(??{$re}))\%\>};
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I guess what I am looking for is a replacement to the [^(\<\%|\%\>)]+ part above (unless that is correct).

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Re^3: RegEx: How to negate more than one character? by jettero (Monsignor) on Mar 25, 2007 at 23:34 UTC
You can proably use a negatively asserted look ahead: `$str =~ m/$pattern(?!ab\|cd)$morepattern/;`. It is a zero-width pattern, but it might do what you want. It's about half-way through perlre. -Paul	[reply] [d/l]