in reply to Re^2: Overloading '=' doesn't DWIM
in thread Overloading '=' doesn't DWIM

I'm not sure if it is relevant--you may be aware already--but I added a couple of printfs to your code:

SV * _copy( SV * arg_obj, SV * second, SV * third ) { Number * num_obj; SV * obj_ref, * obj; printf( "_copy:%p %p %p\n", arg_obj, second, third ); ... SV * _set_from_existing( SV * arg_obj ) { Number * num_obj; SV * obj_ref, * obj; printf( "_set::%p\n", arg_obj ); ...

And it appears that the overloading is not causing your _copy() function to be called:

Finished Build Compile Stage _set::0185E260 555 113 Destroying ...... destroyed Destroying ...... destroyed

Which (as best I can tell) explains the output completely:

$$num1 = Grief::new( 113 ); $num2 = $num1; # Assign using _copy( ) $num3 = _set_from_existing( $num1 ); # Assign using _set_from_existing +( ) _set_val( $num1, 555 ); print _get_val( $num2 ),"\n", _get_val( $num3 ), "\n"; __END__

$num2, in the absence of the overloading is simply an alias to $num1, whereas $num3 is explicitely as new object with the same value. When you set $num1 to 555, you are also setting $num2, as they are both references to the same object.

All of which is probably not news to you. The only real question as far as I can see is if overload can't or won't allow you to overload assignment, why doesn't use overload '=' => \&_copy; throw an error?


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Re^4: Overloading '=' doesn't DWIM
by syphilis (Archbishop) on May 02, 2007 at 01:01 UTC
    And it appears that the overloading is not causing your _copy() function to be called

    Damn!! ... that's the oversight I was ... ummmm ... overlooking. I should've thought to stick a printf() in there as a check. Thanks for picking that up.

    Another approach is to simply comment out the 'use overload ...' code - which has no effect on the output of the script at all. Oh, well .... live and learn ....

    why doesn't use overload '=' => \&_copy; throw an error?

    Good question. Thanks BrowserUK.

    Cheers,
    Rob
    Update: I think, at last, I start to see the light. The overloading of the assignment operator takes its effect only when the value of either $num1 or $num2 is subsequently altered using an overloaded operator. Consider the following:
    use warnings; use Devel::Peek; package Grief; use overload '++' => \&_inc, '=' => \&_copy, ; use Inline C => Config => BUILD_NOISY => 1; use Inline C => <<'EOC'; typedef struct { long num; } Number; SV * new(SV * x) { Number * num_obj; SV * obj_ref, * obj; New(1, num_obj, 1, Number); if(num_obj == NULL) croak("Failed to allocate memory in new() function"); obj_ref = newSViv(0); obj = newSVrv(obj_ref, "Grief"); num_obj->num = SvUV(x); sv_setiv(obj, (IV)num_obj); SvREADONLY_on(obj); return obj_ref; } SV * _get_val(SV * obj) { return newSVuv(((Number*)SvIV(SvRV(obj)))->num); } void _inc(SV * obj, SV * second, SV * third) { (((Number*)SvIV(SvRV(obj)))->num)++; } SV * _copy(SV * arg_obj, SV * second, SV * third) { Number * num_obj; SV * obj_ref, * obj; printf( "_copy:%p %p %p\n", arg_obj, second, third ); New(1, num_obj, 1, Number); if(num_obj == NULL) croak("Failed to allocate memory in _copy() function"); obj_ref = newSViv(0); obj = newSVrv(obj_ref, "Grief"); num_obj->num = ((Number*)SvIV(SvRV(arg_obj)))->num; sv_setiv(obj, (IV)num_obj); SvREADONLY_on(obj); return obj_ref; } void DESTROY(SV * obj) { printf("Destroying ..."); Number * number = (Number*)SvIV(SvRV(obj)); Safefree(number); printf("... destroyed\n"); } EOC $num1 = Grief::new(113); $num2 = $num1; $num3 = _copy($num1, '', ''); #Run any one of the following 4 lines $num1++; # _copy() gets called, 3 objects DESTROYed #$num2++; # _copy() gets called, 3 objects DESTROYed #_inc($num1, '', ''); # no _copy(), 2 objects DESTROYed #_inc($num2, '', ''); # no _copy(), 2 objects DESTROYed print _get_val($num2)," | ", _get_val($num3), "\n";