in reply to hash and array mismatch

that's fairly easy to answer: the hash keys are identical. you might work around this bug with something like the following:
my %keys = keys %data; my $hkey = $data{$i}; if ((my @found = grep /^$hkey$/, %keys) > 1) { $hkey .= '_'; } $dataPos{$hkey} = $i;
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masses are the opiate for religion.

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Re^2: hash and array mismatch
by TGI (Parson) on May 10, 2007 at 17:31 UTC

    I assume your snippet is intended to go inside the OP's for loop:

    foreach my $i ( 0..$#data ) { my %keys = keys %dataPos; # Changed hash name to match hash OP is +building my $hkey = $data[$i]; # Changed data lookup to array to match O +P code. if ((my @found = grep /^$hkey$/, %keys) > 1) { $hkey .= '_'; } $dataPos{$hkey} = $i; print "$data[$i] -- > $i\n"; }

    After I tweaked your code to work with the OP's code, there are still problems. You have a unnecessary nested loop that will grow with each pass through the outer loop. Also, if a key shows up three or more times, the last value will overwrite the value stored for the second key.

    I've fixed these issues below.

    foreach my $i ( 0..$#data ) { my $key = $data[i]; # append '_' until no matching key exists. while ( exists $dataPos{$key} ) { $key .= '_'; } $dataPos{$key} = $i; print "$key -- > $i\n"; }

    Even after its been fixed, I still wouldn't use this approach. I'd store repeated values in arrays as other posters have suggested.


    TGI says moo