in reply to Re^2: Spreading out the elements
in thread Spreading out the elements
S'funny, because I had that solution originally, but then I went back and looked closely at your spec. where I found:
interleave(1, 2);
ABB # BAB and BBA are also fine
And given that "BAB is also acceptable" decided that you might prefer the most diffuse spread possible regardless of whether that meant starting with an 'a' or a 'b'.
To restore the behaviour you are after, just comment out the third line of the sub. See the 2a/3b solution below to see that it works:
#! perl -slw use strict; sub interleave { my( $a, $b ) = qw[ a b ]; my( $as, $bs ) = @_; # ( $a, $as, $b, $bs ) = ( $b, $bs, $a, $as ) if $as < $bs; return $a x $as . $b x $bs unless $as and $bs; ++$bs; my $aPerB = int( $as / $bs ); my $aRem = $as - $bs * $aPerB; my @as = ( $a x $aPerB ) x $bs; my $n = 0; $as[ $n ] .= $a, $as[ - ++$n ] .= $a, $aRem -= 2 while $aRem > 1; $as[ @as / 2 ] .= $a if $aRem > 0; return join $b, @as; } our $N ||= 10; our $S ||= 0; our $M ||= 10; srand $S if $S; for ( 13 .. 19 ) { my( $na, $nb ) = ( $_, 4 ); my $s = interleave( $na, $nb ); my( $as, $bs ) = ( $s =~ tr[a][], $s =~ tr[b][] ); printf "%2da %2db: %s\n", $na, $nb, $s; die "$na != $as or $nb != $bs\n" unless $na == $as and $nb == $bs; } print "\n-----------\n"; for ( 1 .. $N ) { my( $na, $nb ) = map{ int rand $M } 1 .. 2; my $s = interleave( $na, $nb ); my( $as, $bs ) = ( $s =~ tr[a][], $s =~ tr[b][] ); printf "%2da %2db: %s\n", $na, $nb, $s; die "$na != $as or $nb != $bs\n" unless $na == $as and $nb == $bs; } __END__ C:\test>624887 -S=2 -N=20 13a 4b: aaabaabaaabaabaaa 14a 4b: aaabaaabaabaaabaaa 15a 4b: aaabaaabaaabaaabaaa 16a 4b: aaabaaabaaaabaaabaaa 17a 4b: aaaabaaabaaabaaabaaaa 18a 4b: aaaabaaabaaaabaaabaaaa 19a 4b: aaaabaaaabaaabaaaabaaaa ----------- 0a 8b: bbbbbbbb 7a 5b: abababaababa 8a 5b: aabababababaa 4a 8b: ababbbbbbaba 3a 5b: abbbabba 1a 8b: bbbbabbbb 3a 0b: aaa 9a 5b: aabababaababaa 9a 9b: ababababbababababa 2a 8b: abbbbbbbba 3a 9b: abbbbbabbbba 5a 2b: aababaa 4a 7b: ababbbbbaba 1a 0b: a 9a 2b: aaabaaabaaa 2a 3b: abbba 8a 1b: aaaabaaaa 5a 5b: ababbababa 8a 2b: aaabaabaaa 6a 5b: abababababa
You could also substitute 'a' for $a and 'b' for $b in the sub and remove the first line.
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Re^4: Spreading out the elements
by oko1 (Deacon) on Jul 05, 2007 at 03:28 UTC | |
by BrowserUk (Patriarch) on Jul 05, 2007 at 06:47 UTC | |
by oko1 (Deacon) on Jul 05, 2007 at 16:30 UTC |