Re^2: Does redo create a new dynamic scope? (yes)

But the execution of the "loop control block" conditional is skipped, which is why $j is undef after the redo.

This definitely makes sense. I don't know about other readers of this thread but you saved my sanity with this one :)

Comment on Re^2: Does redo create a new dynamic scope? (yes)

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Re^3: Does redo create a new dynamic scope? (yes) by Argel (Prior) on Jul 19, 2007 at 21:19 UTC
I don't know about my sanity, but this has certainly been one of the most interesting threads of late. It's interesting to see some of Perl elites digging under the hood to figure out some perplexing behavior. One of the reason I read this site is to learn tidbits like this.	[reply]