RE: Re: Mode of created files

I'm not sure that I do want umask:
To clarify, the mode I need the files created with is unknown.
What I'm trying to do is to check the mode of a file that already exists, and then create other files that have the same mode (i.e., I don't know what mode the files need to be created with yet).
So my logic would possibly go something like:

1) get mode of file1;
2) create files file2, file3,..., fileN;
3) chmod files file2,..., fileN to the same mode as file1.
[download]

If that makes any more sense...

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RE: RE: Re: Mode of created files by btrott (Parson) on Mar 28, 2000 at 02:53 UTC
You could do that, sure... in that case you just need to use stat to get the mode of the file. `my $mode = (stat "foo")[2];` [download] But I think you could use umask, still... and it may make it easier. Try something like this: `my $mode = (stat "foo")[2]; my $mask = 777 - join '', (($mode&0700)>>6, ($mode&0070)>>3, ($mode&0007)); umask oct $mask;` [download] I'm not sure if this is absolutely right (please someone correct me if it isn't), but it seemed to work for the test cases I tried.	[reply] [d/l] [select]
RE: RE: RE: Re: Mode of created files by setantae (Scribe) on Mar 28, 2000 at 03:17 UTC
Man, I wish I could vote you up twice for this little gem:`join '', (($mode&0700)>>6, ($mode&0070)>>3, ($mode&0007));` That's exactly what I was after! setantae	[reply] [d/l]