syntax error

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

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Re: syntax error by FunkyMonk (Bishop) on Aug 19, 2007 at 17:52 UTC
It should be `=~` (`=` and then `~`).	[reply] [d/l] [select]
Re^2: syntax error by bart (Canon) on Aug 19, 2007 at 20:02 UTC
`=` and then `~` but don't put any whitespace between the two characters, because that's valid too, and means something entirely different! `=` is plain assignment and `~` is the unary bitwise not operator. So it would mean: `$_ is assigned the value of bitwise not the value of (whatever expression, in this case, how many times did the match succeed?)`	[reply] [d/l] [select]
Re^3: syntax error by FunkyMonk (Bishop) on Aug 19, 2007 at 22:19 UTC
Ahhggg. I was trying to help the OP avoid an easily missed mistake, that's why I spelled it out. You're quite right, of course.	[reply] [d/l] [select]
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Re: syntax error by kyle (Abbot) on Aug 19, 2007 at 18:10 UTC
Try this (change "`~=`" to "`=~`"): `for(param()) { push (@num, $_) if $_ =~ m/^d$+/ }` [download]	[reply] [d/l] [select]
Re: syntax error by artist (Parson) on Aug 19, 2007 at 23:32 UTC
`for(param()) { push (@num, $_) if $_ =~ m/^\d$+/ }` [download] You also want to make sure, that it's \d rather than d in the match expression. --Artist	[reply] [d/l]
Re: syntax error by pemungkah (Priest) on Aug 20, 2007 at 07:17 UTC
`for(param()) { push @num, $_ if m/^d$+/ }` will also work -that is, removing `$_` and the erroneous operator altogether - since the default target for a pattern match operation is `$_`. Some will consider this clearer because shorter; others will feel that implied variables in an expression are insufficiently clear. I lean toward the former, myself. It's a matter of personal taste - and whether you'd have to explain it.	[reply] [d/l] [select]