Re: overloading '0+'

0+ is used whenever the variable is used as a number. 0+ is the conversion to a number not just to an integer. So in the line;

my $int = int($soldier1);
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The call to int is one call to truncate and then the assignment is the other.

If you don't have bool overloaded and 0+ is overloaded then, 0+ will be used in a boolean context, which is why truncate is being called in this code;

$soldier ? 1: 0;
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See overload for the all the gory details. (perldoc overload) The sections titled "Boolean, string and numeric conversion" and "Transcendental functions" answer your questions.

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Re^2: overloading '0+' by ikegami (Patriarch) on Sep 02, 2007 at 22:12 UTC
and then the assignment is the other. No. Assignments don't trigger `0+`, and the result of the call to `int` is not an object, so overload doesn't apply to the assignment. I verified this by removing the assignment.	[reply] [d/l] [select]
Re^3: overloading '0+' by bruceb3 (Pilgrim) on Sep 03, 2007 at 05:12 UTC
Your right. My bad. How about this for an explanation; The argument to int is evaluated in numeric context, which calls truncate. Then when there isn't an overload for int, 0+ is used, which calls truncate again ???	[reply]