Re: Two dimensional array

@temp_array is two dimensional.

How do you construct your array?

If your array is an array of rows, each row containing two columns, it should be something like

@array = (
    [ 1, 2 ],
    [ 3, 4 ],
    [ 2, 5 ],
);
[download]

Now, if you want to find the row that contains the values 3, 4

$temp   = 3;
$temp_1 = 4;
@matching_rows = grep { $_->[0] == $temp && $_->[1] == $temp_1 } @arra
+y;
[download]

With the above @array the resulting array consists of one element, which is an anonymous array containing the values 3 and 4. See perlref and perlreftut for the [ ] constructor.

--shmem

_($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                              /\_¯/(q    /
----------------------------  \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

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Re^2: Two dimensional array by Anonymous Monk on Oct 03, 2007 at 20:46 UTC
I have the 2D array built from two arrays containg strings: `@temp_array = (\@arry1, \@arry2); my @exists = grep { $_->[0] eq $temp1 && $_->[1] eq $temp2} @temp_a +rray ;` [download]	[reply] [d/l]
Re^3: Two dimensional array by shmem (Chancellor) on Oct 03, 2007 at 21:01 UTC
Well, that changes things. Sticking to the row/column view, you have arrays of columns. Are those column arrays equal in element number? `my @exists = grep { $temp_array[$_]->[0] eq $temp1 && $temp_array[$_]->[1] eq $temp2 } 0..$#{$temp_array[0]};` [download] The resulting `@exists` will contain the indexes into the two anonymous arrays your `@temp_array` holds where the comparison values are at the same index. --shmem _($_=" "x(1<<5)."?\n".q·/)Oo. G°\ / /\_¯/(q / ---------------------------- \__(m.====·.(_("always off the crowd"))."· ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}	[reply] [d/l] [select]