Having Exporter export through @ISA

satchboost has asked for the wisdom of the Perl Monks concerning the following question:

I've got a base class Foo, which is an Exporter. It has some function foo(), that it exports automatically. (It's some superclass, for example.) I also have Bar which inherits from Foo and Baz which inherits from Bar. So, I have the following:

package Foo;
use Exporter;
@ISA = qw(Exporter);
@EXPORT = qw(foo);

sub foo {}

package Bar;
@ISA = qw(Foo);

package Baz;
@ISA = qw(Bar);
[download]

Now, I want to have foo() be automatically exported into the namespace for Baz the same way it is for Bar. I can't seem to get PERL to do this. Help?

Comment on Having Exporter export through @ISA Download Code

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Re: Having Exporter export through @ISA by merlyn (Sage) on Mar 14, 2001 at 22:22 UTC
Within Bar and Baz, call `Foo->import(qw(foo));`	[reply] [d/l]
(tye)Re: Having Exporter export through @ISA by tye (Sage) on Mar 15, 2001 at 03:29 UTC
I'll just add a friendly warning that mixing inheritance and exporting in a single package is usually a sign of a "confused" interface. - tye (but my friends call me "Tye")	[reply]
Re: Having Exporter export through @ISA by merlyn (Sage) on Mar 14, 2001 at 22:43 UTC
There's no way to 'push' from Foo up into Bar and Baz? I thought that was what the @EXPORT array was for... No, that's not what it's for. There's not "no way". There's just no "polite" way.	[reply]
Re: Having Exporter export through @ISA by satchboost (Scribe) on Mar 14, 2001 at 22:23 UTC
There's no way to 'push' from Foo up into Bar and Baz? I thought that was what the @EXPORT array was for...	[reply]