Re: Weird grep behaviour

Try grep {$var1 eq $_ } instead.

My guess is that grep uses numerical comparison if called with an EXPR (and not a BLOCK), so "a" == "b".

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Re^2: Weird grep behaviour by shmem (Chancellor) on Oct 17, 2007 at 06:08 UTC
No, it's just that `$var1` is "true" for every element in `@arr1`. There's no comparison in the OP. --shmem _($_=" "x(1<<5)."?\n".q·/)Oo. G°\ / /\_¯/(q / ---------------------------- \__(m.====·.(_("always off the crowd"))."· ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}	[reply] [d/l] [select]
Re^2: Weird grep behaviour by naikonta (Curate) on Oct 17, 2007 at 07:36 UTC
It's not about comparison, BLOCK and EXPR are evaluated in boolean context. From OP's sample code, in `grep($var1, @arr1)`, `$var1` is always true. Open source softwares? Share and enjoy. Make profit from them if you can. Yet, share and enjoy!	[reply] [d/l] [select]