Re^2: Looking for N/A twice

You can use a single regex regardless of order if you use look-ahead assertions.

$ perl -le '
> $_ = "gjhgjhgjg sata kjhkhkjhkjhkj N/A khkjhkhkhkj N/A";
> print q{ok} if m{(?ix) (?=.*\bn/a\b.+\bn/a\b) (?=.*\bsata\b)};'
ok
$
[download]

Cheers,

JohnGG

Comment on Re^2: Looking for N/A twice Download Code

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Re^3: Looking for N/A twice by polettix (Vicar) on Oct 22, 2007 at 06:58 UTC
This struck me like a thunder: `m{(?ix) (?=.\bn/a\b.+\bn/a\b) (?=.\bsata\b)}` [download] I thought that the span of application of `(?ix)` was the stuff inside the two parentheses (just like a contracted form of `(?ix:)`), but your regex clearly contradicts this. So I turned to the manpage and... it's there, nicely documented! I love this language. Flavio perl -ple'$_=reverse' <<<ti.xittelop@oivalf Io ho capito... ma tu che hai detto?	[reply] [d/l] [select]

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Re^3: Looking for N/A twice
by polettix (Vicar) on Oct 22, 2007 at 06:58 UTC

m{(?ix) (?=.*\bn/a\b.+\bn/a\b) (?=.*\bsata\b)}
[download]

(?ix)

(?ix:)

Flavio
perl -ple'$_=reverse' <<<ti.xittelop@oivalf

Io ho capito... ma tu che hai detto?

[reply]
[d/l]
[select]