Yes, Foo-> compiles to (&Foo())-> if a sub Foo already exists; otherwise it's ("Foo")->:

$ perl -wl
sub Foo::new{"new in Foo"}
sub Bar::new{"new in Bar"}
print "before sub Foo: ", Foo->new;
sub Foo {"Bar"}
print "after sub Foo: ", Foo->new
__END__
before sub Foo: new in Foo
after sub Foo: new in Bar
[download]

You can disambiguate by saying Foo::->new or "Foo"->new. I prefer the former.