No, SUPER is based on __PACKAGE__, not on ref($self). Quote perlobj,

It is important to note that SUPER refers to the superclass(es) of the current package and not to the superclass(es) of the object.

This is easy to demonstrate.

{
   package Base;
   sub m { print("Boo!\n"); }
}

{
   package Child;
   our @ISA = 'Base';
   bless({}, 'Anything')->SUPER::m();  # Boo!
}
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