Re^2: Can you explain me the output of this programme. especially in the subroutine func2

SORRY !
Bug 6: sanketkathalkar, you are calling func1 & func2 as func1(@arr); and func2(@arr); where you pass array itself, instead of array reference. So when you shift the arguments, you are getting the first element, which is being printed.
ikegami fixed this in the code he posted.

Comment on Re^2: Can you explain me the output of this programme. especially in the subroutine func2 Select or Download Code

Replies are listed 'Best First'.
Re^3: Can you explain me the output of this programme. especially in the subroutine func2 by ikegami (Patriarch) on Nov 26, 2007 at 16:45 UTC
No, that's actually correct for a prototype of `(\@)`. (Notice how `func1(@arr);` worked correctly?) The whole question was about why the prototype wasn't working for `func2`.	[reply] [d/l] [select]
Re^3: Can you explain me the output of this programme. especially in the subroutine func2 by cdarke (Prior) on Nov 26, 2007 at 16:47 UTC
That's one of the things the prototype does. If you specify (\@) then passing an array `func1(@arr)` is correct. Passing `func1(\@arr)` would actually fail the prototype check (as would suppling a list instead of an array). ikegami had to pass a reference because the prototype was removed. Update: my reply overlapped with that of ikegami	[reply] [d/l] [select]
Re^4: Can you explain me the output of this programme. especially in the subroutine func2 by chromatic (Archbishop) on Nov 26, 2007 at 19:33 UTC
Update: my reply overlapped with that of ikegami Why the update? Why apologize for posting correct information?	[reply]