in reply to Re^4: return +0
in thread return +0

And just to close the logic loop (++DrHyde and lidden, btw), this leading plus helps the parser evaluate all those numbers into a single value before printing.

$ perl -e 'print +(2+3)/5' 1

So I assume the author of the code the OP was reading thought there might be some ambiguity and wanted to help the parse out with that return statement.


I humbly seek wisdom.