downer has asked for the wisdom of the Perl Monks concerning the following question:

I am having trouble installing WebService::YouTube. I have installed the package with cpan, and it had many, many dependencies that were required. I try this simple example to test the package: 
my $youtube = WebService::YouTube->new();
my @videos = $youtube->feeds->recently_added;

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i get the following error: Can't locate object method "new" via package "XML::LibXML::SAX" at /usr/lib/perl5/vendor_perl/5.8.5/XML/SAX/ParserFactory.pm line 43.

I am trying to get a feed of all recently added videos on youtube. I cant figure whats going wrong. please help!

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Re: help with WebService::YouTube
by saberworks (Curate) on Nov 28, 2007 at 18:28 UTC
    Sounds like you need to install XML::LibXML::SAX. Sometimes modules you install don't have all the dependencies properly laid out and you have to do it manually.

    XML::LibXML::SAX
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      it seems you are correct with your diagnosis. I get the following error when trying to install that package: The installed version of libxml2 not compatible with XML::LibXML.
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        In the XML::LibXML documentation, in the README file, it says:
        XML::LibXML requires at least libxml2 2.6.16 to compile and pass all tests and at least 2.6.21 is required for XML::LibXML::Reader. For some older OS versions this means that an update of the pre-built packages is required.
        What version of libxml2 do you have? The documentation recommends using xmllint but I don't know what that is, so I found my version like this:
        lozier:~$ xml2-config
Usage: xml2-config [OPTION]

Known values for OPTION are:

  --prefix=DIR          change libxml prefix
  --exec-prefix=DIR     change libxml exec prefix
  --libs                print library linking information
  --cflags              print pre-processor and compiler flags
  --modules             module support enabled
  --help                display this help and exit
  --version             output version information
lozier:~$ xml2-config --version
2.6.23
lozier:~$

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