Re^2: Deconstructed array won't return scalar value if integer?

Yeah, Dumper returns nothing either. Real world code example:

'016' => {
        'ind1' => ' ',
        'ind2' => ' ',
        'subfield' => {
            'a' => {
               'content' => '2009600369'
             }
        }
      },
'546' => {
        'ind1' => ' ',
        'ind2' => ' ',
        'subfield' => {
            'a' => {
                 'content' => 'English'
            }
        }
      },
[download]

Like I said before - 546's content will return English, while 016 will return an uninitialized value

Comment on Re^2: Deconstructed array won't return scalar value if integer? Download Code

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Re^3: Deconstructed array won't return scalar value if integer? by toolic (Bishop) on Nov 29, 2007 at 18:35 UTC
I wonder if the leading 0 in 016 is causing problems. Perhaps when referencing, you could try to force this number to be a string as follows: `$gooddata=$record->{datafield}->{'016'}->{subfield}->{a}->{content};` [download] Just a thought.	[reply] [d/l]
Re^4: Deconstructed array won't return scalar value if integer? by rkmase (Novice) on Nov 29, 2007 at 18:40 UTC
That was exactly it. Thanks again!	[reply]
Re^5: Deconstructed array won't return scalar value if integer? by FunkyMonk (Bishop) on Nov 29, 2007 at 22:36 UTC
Just to make sure you know why. A number that starts with a zero is treated as octal: `print 016, "\n"; print "016", "\n"; print 0+"016", "\n"; #Output: #14 #016 #16` [download]	[reply] [d/l] [select]