Re: Re: $1 doesn't reset?

Yes, thanks for the \G info - but somehow it still works if I use $_ within the for loop.

Also, this now doesn't match anything at all, strangely. Not within while or within a for loop. Only thing I got working is like said within for with $_ as the match.

Btw., thanks for the link to Death to Dot Star, the .*? is save in this place.

Sorry that I didn't mention it before, maybe it's important:
This is perl, v5.6.0 built for i386-linux
--
Alfie

Comment on Re: Re: $1 doesn't reset?

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Re: Re: Re: $1 doesn't reset? by andye (Curate) on Mar 20, 2001 at 17:56 UTC
alfie, my understanding is this (and I'm relying on more knowledgable monks to correct me if I'm misunderstanding): Working with $_, not $1, is the correct behaviour in the for loop. Because: - the regexp match produces a list - the for(each) loop cycles through each element of the list, assigning them to $_ as it goes. So... $1 doesn't contain each match in turn, because the regexp is only executed once, and the matches are put into $1 to $n, and into a list, and the loop goes round the list, aliasing $_ to each element in turn. If you want to use $1, then Corion's suggestion of \G should do the biz. But it looks to me as though the for loop and $_ would be more efficient. andy.	[reply]

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Re: Re: Re: $1 doesn't reset?
by andye (Curate) on Mar 20, 2001 at 17:56 UTC

alfie

mis

Working with $_, not $1, is the correct behaviour in the for loop. Because:
- the regexp match produces a list
- the for(each) loop cycles through each element of the list, assigning them to $_ as it goes.

So... $1 doesn't contain each match in turn, because the regexp is only executed once, and the matches are put into $1 to $n, and into a list, and the loop goes round the list, aliasing $_ to each element in turn.

If you want to use $1, then Corion's suggestion of \G should do the biz. But it looks to me as though the for loop and $_ would be more efficient.

andy.

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