Re: Modify a hash via its reference

Philippe:

The problem is that your Modify_Hash_1 routine is accepting the hash ref, and then throwing the reference away by assigning it a new value. By modifying your Modify_Hash_1 routine to the following, you can change the values in %Fruits.

sub Modify_Hash_1 {
  my ( $Ref_to_Hash ) = @_;
  $Ref_to_Hash->{Apples}=5;

# This line would discard the reference to %Fruits, and create a *new*
+ 
# hash with the specified values
#  $Ref_to_Hash = { "Pears", 5, "Peaches", 7 };
};
[download]

...roboticus

Update: s/discards/discard/, s/taking/accepting/, added code tags in explanatory text.

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Re^2: Modify a hash via its reference by bart (Canon) on Jan 23, 2008 at 12:36 UTC
Good work. `# This line would discard the reference to %Fruits, and create a new # hash with the specified values # $Ref_to_Hash = { "Pears", 5, "Peaches", 7 };` [download] The solution is to not change the reference, but the dereferenced hash: `%$Ref_to_Hash = ( "Pears", 5, "Peaches", 7 );` [download]	[reply] [d/l] [select]