Re: regexp list return 5.6 vs 5.8

i don't have access to 5.6 at the moment and so cannot investigate your question, but just as a matter of curiosity, why use the expression return @rv[ 0 .. $#rv ]; when it seems to me it will return exactly the same thing as return @rv; and when the latter expression does not involve the behavior of the .. range operator in the case where the terminal value is less than the initial value, i.e., 0 .. -1 in the case of $#rv when the array @rv is empty?

(you haven't been messing with $[ have you?)

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Re^2: regexp list return 5.6 vs 5.8 by Anonymous Monk on Jan 24, 2008 at 08:27 UTC
hmmm... ok, but then wouldn't it be better (in the sense of being more maintainable) to write something like `return wantarray ? @rv : $rv[-1];` ?	[reply] [d/l]
Re^2: regexp list return 5.6 vs 5.8 by Sixtease (Friar) on Jan 24, 2008 at 07:50 UTC
It's not quite the same ^^. @rv is an array and in scalar context evaluates to the number of the emelents. Slicing turns it into a list and thus gives the last element instead. use strict; use warnings; print "Just Another Perl Hacker\n";	[reply]
Re^3: regexp list return 5.6 vs 5.8 by shmem (Chancellor) on Jan 24, 2008 at 08:31 UTC
ETOOMUCHMAGIC. If that is what you want, state it: `return wantarray ? @rv : pop @rv;` [download] Is the behavior of list slice subroutine return an intended feature, is it specced somewhere (or even documented)? Or is it just an implementation detail which might some day be considered a bug and be changed thereafter? Don't golf production code ;-) --shmem _($_=" "x(1<<5)."?\n".q·/)Oo. G°\ / /\_¯/(q / ---------------------------- \__(m.====·.(_("always off the crowd"))."· ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}	[reply] [d/l]