but i forgot how to create a new thread...

what does this mean? print qq{$1}

print "$1"
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Double-quotes allow interpolation of variables. So, if the variable $1 has the value "foo", then "foo" will be printed. $1 is a special variable which is set upon a successful regular expression match (see perlre).

• Click on Seekers of Perl Wisdom (at the upper right hand corner of your screen).
• When the new page appears, go to the bottom of the page.
• Populate the Add your Question title and message boxes.
• Preview, Preview, Preview, create

• Get the string stored in $1; use it as the key into a hash named %qq; print the value of that hash element. There should only be one value, by definition.
• Revised:Get the number stored in $1; use it as the index into an array named @qq; print the value of that array element. There should only be one value, by definition.
• Try this (though, since this is either homework or an exam, I may be playing with your head. Good luck...):

  if ( /^(\d*).+(\d*)$/ )
      {
  #      $1 containing the starting numeric string, if any.
  #      $2 contains the terminating numeric string, if any.
      }
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a hash named %qq

I don't think so. The OP asked about qq{$1}, not $qq{$1}.

Are those parens? They looked like curly braces to me. Thanks for the heads up.

(Or I could say sssshhhhh, I'm messing up his homework...)

thanks apl

Mercury.