mpatharkar has asked for the wisdom of the Perl Monks concerning the following question:

Hi all,

I have one input file "pick no.txt" from which i have to find perticuler pattern and print it in to output file "Numbers.txt".

The input file is "pick no.txt"


Number:
Number-1999-1011
----------------------------------------
Number:
Number-1999-0696
----------------------------------------
Number:
Number-1999-0833,Number-2004-0786,Number-2004-0747,Number-2004-075,Number-2004-0748,Number-2004-0809
----------------------------------------
Number:
Number-2000-1209
----------------------------------------

The perl script i made for this is..
#!/usr/bin/perl

open (RD, "pick no.txt") or die"Could not open file";
@Read = <RD>; close (RD);

open (WR1, ">>Numbers.txt") or die"Could not open file";

for ($i=0; $i<= $#Read; $i++)
{
 if($Read[$i] =~/^Number:/and $Read[$i+1]=~/(\w\w\w\w\w\w-\d\d\d\d-\d\
+d\d\d)/)
 {
  
  $Number = $1;
  $Number1 = substr ($Number, 7, 9);
  print "$Number1\n";
  print WR1"$Number1\n";
 } 
}

[download]


The output of the script is Numbers.txt..

1999-1011
1999-0696
1999-0833
2000-1209
The problem with this is it is not useful to search pattern occurance more than once in the same line. The numers after 1999-0833 is not shown in thw output.
Any suggestions for this?


--Mahesh

Replies are listed 'Best First'.
Re: how to search a pattern occured more than once in line
by moritz (Cardinal) on Jan 29, 2008 at 07:45 UTC
    You can use the /g modifier, and replace the if by a while (untested): 
    for (@Read){
    while (m/Number-(\d{4}-\d{4})/g){
         print "$1\n";
         print WR1 "$1\n";
    }
}

    [download]

    By putting the parenthesis only around these parts of the regex that you want to capture, you avoid the substr alltogether.

    \d{4} is short for \d\d\d\d

[reply]
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Re: how to search a pattern occured more than once in line
by svenXY (Deacon) on Jan 29, 2008 at 07:58 UTC
    Hi,
    I'd go with split: 
    #!/usr/bin/perl

use strict;
use warnings;

my @Read = <DATA>;

for (@Read){
  next unless /^Number-/;
  chomp;
  $_ =~ s/Number-//g;
  my @numbers = split(/,/);
  print join("\n", @numbers),"\n";
}

__DATA__
Number:
Number-1999-1011
----------------------------------------
Number:
Number-1999-0696
----------------------------------------
Number:
Number-1999-0833,Number-2004-0786,Number-2004-0747,Number-2004-075,Num
+ber-2004-0748,Number-2004-0809
----------------------------------------
Number:
Number-2000-1209
----------------------------------------

    [download]
    output: 
    1999-1011
1999-0696
1999-0833
2004-0786
2004-0747
2004-075
2004-0748
2004-0809
2000-1209

    [download]

    Regards,
    svenXY

    update: I personally prefer the solution moritz++ offered above. It's also more regex-like - as was asked for in the OP.

[reply]
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Re: how to search a pattern occured more than once in line
by parv (Parson) on Jan 29, 2008 at 07:49 UTC
[reply]

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