Re: Why is Zero not 0?

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Re^2: Why is Zero not 0? by Joost (Canon) on Feb 01, 2008 at 23:25 UTC
IIRC the -0.00 representation happens when you're using sprintf("%0.2f",$some_number_very_slighty_less_than_zero). The last two digits happen because they were specified in the format string. the minus sign is supposedly because that's how the C stdio lib does that. update: `#include "stdio.h" int main() { printf("%0.2f\n",-0.000000000000000000000000001); }` [download] `$ ./a.out -0.00` [download] "What should it profit a man, if he should win a flame war, yet lose his cool?"	[reply] [d/l] [select]
Re^3: Why is Zero not 0? by syphilis (Archbishop) on Feb 03, 2008 at 03:57 UTC
I think that, so long as the number is less than zero && the number rounds to zero, then we get a leading "-0". Hence: `C:\C>perl -e "printf \"%0.2f\", -0.0049" -0.00 C:\C>perl -e "printf \"%.0f\", -0.499" -0` [download] Cheers, Rob	[reply] [d/l]
Re^4: Why is Zero not 0? by Joost (Canon) on Feb 03, 2008 at 14:02 UTC
Yes, that's a clearer way of putting it. Note that it's only true for %f formatting, though: `$ perl -e'printf("%d,%0.f\n",-0.1,-0.1)' 0,-0` [download] "What should it profit a man, if he should win a flame war, yet lose his cool?"	[reply] [d/l]