Re: How can I build regexp with "not" assertion?

Given your example, if you are trying to do substitutions on all the lines which match all the 2-numbered lines, just ignore the "not parts" ...

$line =~ s/(pattern1).+?pattern2.+?\1/substitute/;
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... Above will work since "pattern2" does not appear (per your example) in any lines identified by the 1s, so they remain unchanged.

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Re^2: How can I build regexp with "not" assertion? by putnik (Novice) on Feb 17, 2008 at 17:36 UTC
Thank you, but sorry, it work in wrong way. I tried this, but got `1stline....subst... 1a line....subst.....` [download] I mean it substituted all in parenthesis this way: `1stline....(pattern1.......pattern1..... 2ndline....pattern1.....pattern2...pattern1)...` [download] I CAN'T split it in lines, i must treat all dada as a single line because \n may appear in any place	[reply] [d/l] [select]