in reply to How can I build regexp with "not" assertion?

This will probably work, depending on what pattern1 and pattern2 really are: 
/
   pattern1
   (?:(?!pattern1).)*
   pattern2
   (?:(?!pattern1).)*
   pattern1
/x

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Re^2: How can I build regexp with "not" assertion?
by putnik (Novice) on Feb 22, 2008 at 14:09 UTC
    THANK YOU! THANK YOU! THANK YOU!
    It greatly work.
    Googd Luck!
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